y^'+2ty=4t

Lösung

y^{^{'}} + 2 t y = 4 t

y = e^{- t^{2} + c_{1}} + 2

Schritte zur Lösung

y^{'} (t) + 2 t y = 4 t

Solve separable ODE:

y = e^{- t^{2} + c_{1}} + 2

y = e^{- t^{2} + c_{1}} + 2

\frac{d y}{d x} = 5 x^{3} y

y^{^{'}} = \frac{1}{2} (y^{2} + 1)

\frac{d y}{d x} + 3 x y = x

\frac{d y}{d x} + 3 x y = 0

\frac{d y}{d x} = y (x^{2} - 3 x + sin (2 x))^{2}