2xdx+3y^2dy=0

Lösung

2 x d x + 3 y^{2} d y = 0

y = 3 - x^{2} + c_{1}

Schritte zur Lösung

2 x d x + 3 y^{2} d y = 0

Solve separable ODE:

y = 3 - x^{2} + c_{1}

y = 3 - x^{2} + c_{1}

\frac{d x}{d t} = t (1 + x^{2})

y^{^{'}} + (\frac{( x - 2 )}{( x - 1 )}) \cdot y = 0

y = 8 y^{^{'}}

y^{^{'}} = (\frac{y}{x})^{2}

\frac{d v}{d t} = 6 - 3 v