y^2y^'=2(t+ty^3)e^{t^2}

Lösung

y^{2} y^{^{'}} = 2 (t + t y^{3}) e^{t^{2}}

y = 3 e^{3 e^{t^{2}} - c_{1}} - 1

Schritte zur Lösung

y^{2} y^{'} (t) = 2 (t + t y^{3}) e^{t^{2}}

Solve separable ODE:

y = 3 e^{3 e^{t^{2}} - c_{1}} - 1

y = 3 e^{3 e^{t^{2}} - c_{1}} - 1

x^{^{'}} = - x^{3}

3 \frac{d x}{d t} + 2 x = 4, x = 0

u^{^{'}} = 2 e^{3 x - H (x)}

\frac{d y}{d x} - 8 \frac{d y}{d x} + 16 y = 0

y^{^{'}} = x (6 - y)