y-yy^'+2y=cos(8)

解

y - y y^{^{'}} + 2 y = cos (8)

y = \frac{cos ( 8 ) W ( - \frac{1}{c o s ( 8 ) e ^{\frac{- 9 t - c _{1}}{c o s ( 8 )}}} )}{3} + \frac{cos ( 8 )}{3}

解答ステップ

y - y y^{'} (t) + 2 y = cos (8)

分離可能 ODE を解く:

y = \frac{cos ( 8 ) W ( - \frac{1}{c o s ( 8 ) e ^{\frac{- 9 t - c _{1}}{c o s ( 8 )}}} )}{3} + \frac{cos ( 8 )}{3}

y = \frac{cos ( 8 ) W ( - \frac{1}{c o s ( 8 ) e ^{\frac{- 9 t - c _{1}}{c o s ( 8 )}}} )}{3} + \frac{cos ( 8 )}{3}