10yy^'=x,y(10)=9

Lösung

10 y y^{^{'}} = x, y (10) = 9

y = \frac{x ^{2}}{10} + 71

Schritte zur Lösung

10 y y^{'} (x) = x

Solve separable ODE:

y = \frac{x ^{2}}{10} + 71

y = \frac{x ^{2}}{10} + 71

\frac{d y}{d x} = 1 - 0.4 y

\frac{d y}{d x} = y^{2} - 5 y + 6

(1 - x^{2}) \cdot \frac{d y}{d x} = 2 y

y^{^{'}} = 4 - 2 y

\frac{d y}{d x} = 2 x y - y