y^'+xy= x/(y^2)

Lösung

y^{^{'}} + x y = \frac{x}{y ^{2}}

y = 3 - e^{- \frac{3 x ^{2}}{2} - c_{1}} + 1

Schritte zur Lösung

y^{'} (x) + x y = \frac{x}{y ^{2}}

Solve separable ODE:

y = 3 - e^{- \frac{3 x ^{2}}{2} - c_{1}} + 1

y = 3 - e^{- \frac{3 x ^{2}}{2} - c_{1}} + 1

\frac{d y}{d x} = \frac{3 y}{x + 6}

y^{^{'}} [t] = 0.3 y [t]

32 = v^{2} + xv \frac{d v}{d x}

\frac{d y}{d x} = y^{2} + 2 y - 15

y^{^{'}} = x y^{3} (1 + x^{2})^{(\frac{- 1}{2})}