xy^2y^'=x+x^3

Lösung

x y^{2} y^{^{'}} = x + x^{3}

y = 3 3 x + x^{3} + c_{1}

Schritte zur Lösung

x y^{2} y^{'} (x) = x + x^{3}

Solve separable ODE:

y = 3 3 x + x^{3} + c_{1}

y = 3 3 x + x^{3} + c_{1}

\frac{3 d y}{d t} = \frac{cos ( t )}{y}

e^{x + y} \cdot y^{^{'}} = x

y^{^{'}} = y + 3 y sin (3 t), y (0) = 4

\frac{d P}{d t} = 0.05 P - 0.00125 P^{2}

x^{2} d x = \frac{1}{y ^{2}} d y