6y^'-3e^{2x}y=0,y(0)=4

Lösung

6 y^{^{'}} - 3 e^{2 x} y = 0, y (0) = 4

y = 4 e^{\frac{e ^{2 x} - 1}{4}}

Schritte zur Lösung

6 y^{'} (x) - 3 e^{2 x} y = 0

Solve separable ODE:

y = 4 e^{\frac{e ^{2 x} - 1}{4}}

y = 4 e^{\frac{e ^{2 x} - 1}{4}}

y^{^{'}} \cdot sin^{2} (x) = cos (x) (1 - 3 y)

x^{3} y d x + 9 d y = 0

y^{^{'}} = 2 y^{2} \cdot e^{- x^{2}}, y (0) = 1

\frac{d y}{d x} = - \frac{7}{2} x^{7} y^{6}

y^{^{'}} = x sin (y)