yy^'=3cos(2x)

Lösung

y y^{^{'}} = 3 cos (2 x)

y = 3 sin (2 x) + c_{1}, y = - 3 sin (2 x) + c_{1}

Schritte zur Lösung

y y^{'} (x) = 3 cos (2 x)

Solve separable ODE:

y = 3 sin (2 x) + c_{1}, y = - 3 sin (2 x) + c_{1}

y = 3 sin (2 x) + c_{1}, y = - 3 sin (2 x) + c_{1}

y d y + 2 x d x - 1 d x = 0

\frac{d y}{d x} = y \cdot x^{2} - 1.1 y

\frac{4 t x d x}{d t} = x^{2} + 1

\frac{d}{d x} (cos (y) + 2) = 2 x

y^{^{'}} - b y = 0