x^'=x^2t

Lösung

x^{^{'}} = x^{2} t

x = - \frac{2}{t ^{2} + c _{1}}

Schritte zur Lösung

x^{'} (t) = x^{2} t

Solve separable ODE:

x = - \frac{2}{t ^{2} + c _{1}}

x = - \frac{2}{t ^{2} + c _{1}}

y \cdot d x = (- 1 + x) d y

e^{- 2 y} \frac{d y}{d x} = x - 2

\frac{d x}{d y} = e^{x}

3 e^{- 2 y} x^{2} + 8 x e^{- 2 y} = \frac{d y}{d x}

2 y y^{^{'}} = 1 + (y^{^{'}}) 2