yy^'=-5x

解答

y y^{^{'}} = - 5 x

y = - 5 x^{2} + c_{1}, y = - - 5 x^{2} + c_{1}

求解步骤

y y^{'} (x) = - 5 x

求解可分离方程:

y = - 5 x^{2} + c_{1}, y = - - 5 x^{2} + c_{1}

y = - 5 x^{2} + c_{1}, y = - - 5 x^{2} + c_{1}

\frac{d y}{d x} - \frac{2 x}{x ^{2} + 1} y = - \frac{2 x}{x ^{2} + 1}

(y^{2} + 3) d x = y sec^{2} (x) d y

(x^{3} + x^{3}) d x = x y^{2} d y

y^{^{'}} - a \cdot e^{- b \cdot y} = 0

\frac{d v}{d t} = 1 - 3 v