y^'=(1+y^2)*cos(t)

Lösung

y^{^{'}} = (1 + y^{2}) \cdot cos (t)

y = tan (sin (t) + c_{1})

Schritte zur Lösung

y^{'} (t) = (1 + y^{2}) \cdot cos (t)

Solve separable ODE:

y = tan (sin (t) + c_{1})

y = tan (sin (t) + c_{1})

y^{^{'}} = x y + 4 x + 3 y + 12

\frac{d y}{d x} y = tan (x^{2} + 1)

\frac{d y}{d x} = x \cdot e^{- y}

x d y = (y^{- 3} - y) d x

\frac{d y}{d t} = 2 t y