y^'tan(x)=7a+y,y(pi/3)=7a

Lösung

y^{^{'}} tan (x) = 7 a + y, y (\frac{π}{3}) = 7 a

y = \frac{28 a sin ( x )}{3} - 7 a

Schritte zur Lösung

y^{'} (x) tan (x) = 7 a + y

Solve separable ODE:

y = \frac{28 a sin ( x )}{3} - 7 a

y = \frac{28 a sin ( x )}{3} - 7 a

y^{^{'}} = - x e^{y}

y^{^{'}} = tan (y) x

\frac{d y}{d x} = x y^{2} sin (x)

y^{^{'}} = 2 - 0.1 y, y (0) = 0

x^{^{'}} = \frac{1 + x ^{2}}{1 + t ^{2}}