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Popular >

y^'=4y-3

Solution

y^{^{'}} = 4 y - 3

Solution

y = \frac{e ^{4 t + c_{1}}}{4} + \frac{3}{4}

Solution steps

y^{'} (t) = 4 y - 3

Solve separable ODE:

y = \frac{e ^{4 t + c_{1}}}{4} + \frac{3}{4}

y = \frac{e ^{4 t + c_{1}}}{4} + \frac{3}{4}

Graph

Popular Examples

(dy)/(dx)=(x^2+x)/(y+3)

\frac{d y}{d x} = \frac{x ^{2} + x}{y + 3}

y^'=-(0.1y)/(0.5-0.1x)

y^{^{'}} = - \frac{0.1 y}{0.5 - 0.1 x}

(dN)/(dt)=k(20-N)

\frac{d N}{d t} = k (20 - N)

(dy)/(dt)=0.06y+3000,y(0)=70000

\frac{d y}{d t} = 0.06 y + 3000, y (0) = 70000

(dy)/(dx)y=u^2+2u,u= 1/(x^2)

\frac{d y}{d x} y = u^{2} + 2 u, u = \frac{1}{x ^{2}}

Frequently Asked Questions (FAQ)

What is the solution for y^'=4y-3 ?
The solution for y^'=4y-3 is y=(e^{4t+c_{1}})/4+3/4