y^'=xy-8x

Lösung

y^{^{'}} = x y - 8 x

y = e^{\frac{x ^{2}}{2} + c_{1}} + 8

Schritte zur Lösung

y^{'} (x) = x y - 8 x

Solve separable ODE:

y = e^{\frac{x ^{2}}{2} + c_{1}} + 8

y = e^{\frac{x ^{2}}{2} + c_{1}} + 8

x^{^{'}} = - (1 - x) (2 - x)

\frac{d y}{d t} = 10 y - 2 y^{2}

\frac{d y}{d x} = (\frac{2 x + x y ^{2}}{4 y + y x ^{2}})

\frac{d y}{d x} = x y^{2}, y (1) = 1

y^{^{'}} - 5 x^{3} e^{y} = 0