y^'=4t(y-1)

Lösung

y^{^{'}} = 4 t (y - 1)

y = e^{2 t^{2} + c_{1}} + 1

Schritte zur Lösung

y^{'} (t) = 4 t (y - 1)

Solve separable ODE:

y = e^{2 t^{2} + c_{1}} + 1

y = e^{2 t^{2} + c_{1}} + 1

x (y^{2} + \frac{d y}{d x}) + x^{2} y \frac{d y}{d x} = - y

y^{^{'}} = \frac{y}{25 t ^{2} + 1}

y^{^{'}} = x y + 3 x

(x^{2} - x) y^{^{'}} + (3 - 2 x) y = 0

y^{^{'}} sec (t) = \frac{- y ^{9}}{8}