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Beliebt Rechnen >

(1+e^x)y-(x+e^x)y^'=0

Lösung

(1 + e^{x}) y - (x + e^{x}) y^{^{'}} = 0

Lösung

y = e^{c_{1}} x + e^{c_{1} + x}

Schritte zur Lösung

(1 + e^{x}) y - (x + e^{x}) y^{'} (x) = 0

Solve separable ODE:

y = e^{c_{1}} x + e^{c_{1} + x}

y = e^{c_{1}} x + e^{c_{1} + x}

Graph

Beliebte Beispiele

y^'=(x^2)/(y^2),y(2)=4

y^{^{'}} = \frac{x ^{2}}{y ^{2}}, y (2) = 4

(dy)/(dx)=(2x+2xy^2)/(y+2x^2y)

\frac{d y}{d x} = \frac{2 x + 2 x y ^{2}}{y + 2 x ^{2} y}

y^'+(3x)/(x^2+1)y=(6x)/(x^2+1)

y^{^{'}} + \frac{3 x}{x ^{2} + 1} y = \frac{6 x}{x ^{2} + 1}

x y^{^{'}} = y - 1

(dy)/(dx)=(16xy)/((ln(y))^2)

\frac{d y}{d x} = \frac{16 x y}{( ln ( y ) ) ^{2}}