y^'=y^2+9

Lösung

y^{^{'}} = y^{2} + 9

y = 3 tan (3 t + c_{1})

Schritte zur Lösung

y^{'} (t) = y^{2} + 9

Solve separable ODE:

y = 3 tan (3 t + c_{1})

y = 3 tan (3 t + c_{1})

\frac{d y}{d x} = 10 - \frac{30}{y}, y (0) = 500

y^{^{'}} = \frac{3 x y + y}{3 x ^{2}}

x^{2} \frac{d y}{d x} + x y = y

y d x = 3 x d y

\frac{d}{d x} ((y) \cdot 10) = - x \cdot y