(p-1)y^'(p)+3y(p)=0

Lösung

(p - 1) y^{^{'}} (p) + 3 y (p) = 0

y (p) = \frac{c _{1}}{p ^{3} - 3 p ^{2} + 3 p - 1}

Schritte zur Lösung

(p - 1) y^{'} (p) + 3 y (p) = 0

Solve separable ODE:

y (p) = \frac{c _{1}}{p ^{3} - 3 p ^{2} + 3 p - 1}

y (p) = \frac{c _{1}}{p ^{3} - 3 p ^{2} + 3 p - 1}

y^{^{'}} - y - 1 = 0

y^{^{'}} = \frac{- x - x y}{y + x y}

x y y^{^{'}} = ln (x)

\frac{d y}{d t} - 3 y = 0

\frac{d y}{d x} = (x - 7) e^{- 2 y}, y (7) = ln (7)