(t^2-16t+48)((dy)/(dt))=y

Lösung

(t^{2} - 16 t + 48) (\frac{d y}{d t}) = y

y = \frac{c _{1} 8 t - 12}{8 t - 4}

Schritte zur Lösung

(t^{2} - 16 t + 48) (\frac{d y}{d t}) = y

Solve separable ODE:

y = \frac{c _{1} 8 t - 12}{8 t - 4}

y = \frac{c _{1} 8 t - 12}{8 t - 4}

\frac{d z}{d t} = 2 t e^{6 z}

\frac{d}{d x} ((y) \cdot 10) + 5 y = 5

x + y x d x - d y = 0, y^{2} = 4

y^{^{'}} + x y = x y^{- 3}

x y^{^{'}} = (x + 1) e^{- y}