What is the solution for 8(dy)/(dx)+1x^2y=72x^2 ?

The solution for 8(dy)/(dx)+1x^2y=72x^2 is y=e^{-(x^3)/(24)+c_{1}}+72

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8(dy)/(dx)+1x^2y=72x^2

8 \frac{d y}{d x} + 1 x^{2} y = 72 x^{2}

y = e^{- \frac{x ^{3}}{24} + c_{1}} + 72

Solution steps

8 \frac{d y}{d x} + 1 x^{2} y = 72 x^{2}

Solve separable ODE:

y = e^{- \frac{x ^{3}}{24} + c_{1}} + 72

y = e^{- \frac{x ^{3}}{24} + c_{1}} + 72

y^{^{'}} = \frac{( y + 4 )}{x}

1 + y^{2} d x - y (1 + x^{2}) d y = 0

f (x) = \frac{x}{sin ( x )} f^{^{'}} (x)

\frac{d}{d θ} (ln (y (θ))) = \frac{θ - 8}{θ cos ( θ )}

\frac{d y}{d x} x = sec (y)

What is the solution for 8(dy)/(dx)+1x^2y=72x^2 ?
The solution for 8(dy)/(dx)+1x^2y=72x^2 is y=e^{-(x^3)/(24)+c_{1}}+72