y^'=11ty-16y,y(0)=4

Lösung

y^{^{'}} = 11 t y - 16 y, y (0) = 4

y = 4 e^{\frac{11 t ^{2}}{2} - 16 t}

Schritte zur Lösung

y^{'} (t) = 11 t y - 16 y

Solve separable ODE:

y = 4 e^{\frac{11 t ^{2}}{2} - 16 t}

y = 4 e^{\frac{11 t ^{2}}{2} - 16 t}

3 y^{^{'}} - 3 e^{2 x} y = 0, y (0) = 1

\frac{d x}{d t} = t (x - 2)

\frac{d y}{d x} = \frac{8 sin ( x )}{sin ( y )}, y (0) = \frac{π}{2}

\frac{d}{d t} ((y) (8 y - y^{2})) = - \frac{8}{144} y, y (0) = 8

y d y = x (1 + x^{2})^{\frac{- 1}{2}} (1 + y^{2})^{\frac{1}{2}} d x