(dv)/(dt)+v+v^2=0

Lösung

\frac{d v}{d t} + v + v^{2} = 0

v = - \frac{1}{1 - e ^{t + c_{1}}}

Schritte zur Lösung

\frac{d v}{d t} + v + v^{2} = 0

Solve separable ODE:

v = - \frac{1}{1 - e ^{t + c_{1}}}

v = - \frac{1}{1 - e ^{t + c_{1}}}

y y^{^{'}} = x 1 - y^{2}

d v = cos (x) d x

y^{^{'}} \cdot sin (x) + y = 0

(1 + y) d x + \frac{d y}{x ^{2} - 2 x} = 0

5 y^{4} d y = 6 x d x