What is the derivative of x^2,x+2xcos(x-2sec(x)) ?

The derivative of x^2,x+2xcos(x-2sec(x)) is (,(2xx+1*x^2))+2(cos(x)-xsin(x))-2sec(x)tan(x)

What is the first derivative of x^2,x+2xcos(x-2sec(x)) ?

The first derivative of x^2,x+2xcos(x-2sec(x)) is (,(2xx+1*x^2))+2(cos(x)-xsin(x))-2sec(x)tan(x)

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\frac{d}{d x} (x^{2}, x + 2 x cos (x) - 2 sec (x))

(, (2 xx + 1 \cdot x^{2})) + 2 (cos (x) - x sin (x)) - 2 sec (x) tan (x)

Solution steps

\frac{d}{d x} (x^{2}, x + 2 x cos (x) - 2 sec (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}, x) + \frac{d}{d x} (2 x cos (x)) - \frac{d}{d x} (2 sec (x))

\frac{d}{d x} (x^{2}, x) = (, (2 xx + 1 \cdot x^{2}))

\frac{d}{d x} (2 x cos (x)) = 2 (cos (x) - x sin (x))

\frac{d}{d x} (2 sec (x)) = 2 sec (x) tan (x)

= (, (2 xx + 1 \cdot x^{2})) + 2 (cos (x) - x sin (x)) - 2 sec (x) tan (x)

\frac{d}{d x} (ln (2 cos (x)))

x^{3} - x^{2} - x, x

y = - x, y = - 8 x + 13, [0, \frac{13}{8}]

(2 x + 1) \frac{d y}{d x} = 4

\int \frac{1}{4 + 5 x ^{6}} (30 x^{5}) d x

What is the derivative of x^2,x+2xcos(x-2sec(x)) ?
The derivative of x^2,x+2xcos(x-2sec(x)) is (,(2xx+1*x^2))+2(cos(x)-xsin(x))-2sec(x)tan(x)
What is the first derivative of x^2,x+2xcos(x-2sec(x)) ?
The first derivative of x^2,x+2xcos(x-2sec(x)) is (,(2xx+1*x^2))+2(cos(x)-xsin(x))-2sec(x)tan(x)