y^'=0.1(y-20)

Lösung

y^{^{'}} = 0.1 (y - 20)

y = e^{0.1 t + c_{1}} + 20

Schritte zur Lösung

y^{'} (t) = 0.1 (y - 20)

Solve separable ODE:

y = e^{0.1 t + c_{1}} + 20

y = e^{0.1 t + c_{1}} + 20

\frac{d}{d x} (x^{5} + y^{4}) = \frac{d}{d x} (500)

\frac{d y}{d x} + 2 y = 19

y^{^{'}} - \frac{( x ^{2} - 2 )}{x} y = 0

y^{^{'}} - y^{2} e^{- x} = 0

y^{^{'}} = \frac{t}{sin ( y )}