(dy)/(dx)y=(2x+1)/(xsin(x))

Lösung

\frac{d y}{d x} y = \frac{2 x + 1}{x sin ( x )}

y = 2 \cdot \int \frac{2 x + 1}{x sin ( x )} d x, y = - 2 \cdot \int \frac{2 x + 1}{x sin ( x )} d x

Schritte zur Lösung

\frac{d y}{d x} y = \frac{2 x + 1}{x sin ( x )}

Solve separable ODE:

y = 2 \cdot \int \frac{2 x + 1}{x sin ( x )} d x, y = - 2 \cdot \int \frac{2 x + 1}{x sin ( x )} d x

y = 2 \cdot \int \frac{2 x + 1}{x sin ( x )} d x, y = - 2 \cdot \int \frac{2 x + 1}{x sin ( x )} d x

y^{^{'}} - b y = 2

x^{^{'}} = x^{2} - 4

y^{^{'}} = e^{2 x - 2 y}

\frac{d y}{d x} = a (y^{2} + 4)

\frac{d V}{d t} = 3 - 8 V