(x^2+1)y+2xy^'+(e^x)xy=0

Lösung

(x^{2} + 1) y + 2 x y^{^{'}} + (e^{x}) x y = 0

y = \frac{e ^{\frac{- x ^{2} - 2 e ^{x} + c _{1}}{4}}}{x}

Schritte zur Lösung

(x^{2} + 1) y + 2 x y^{'} (x) + (e^{x}) x y = 0

Solve separable ODE:

y = \frac{e ^{\frac{- x ^{2} - 2 e ^{x} + c _{1}}{4}}}{x}

y = \frac{e ^{\frac{- x ^{2} - 2 e ^{x} + c _{1}}{4}}}{x}

7 t y^{^{'}} + y = 0

x y^{^{'}} \cdot y = x^{2} sin (x)

\frac{d v}{d t} = - 0.004 v^{2}

x sin (y) d x + cos (y) (1 + x^{2}) d y = 0

\frac{d z}{d t} + 9 e^{8 t + 4 z} = 0