y^'=((x^2y^2))/8+y^2

解答

y^{^{'}} = \frac{( x ^{2} y ^{2} )}{8} + y^{2}

y = - \frac{24}{x ^{3} + 24 x + c _{1}}

求解步骤

y^{'} (x) = \frac{( x ^{2} y ^{2} )}{8} + y^{2}

求解可分离方程:

y = - \frac{24}{x ^{3} + 24 x + c _{1}}

y = - \frac{24}{x ^{3} + 24 x + c _{1}}

\frac{d y}{d x} 6 x^{3} y + 2 y = 0

y^{^{'}} = 3 - 5 y

\frac{d y}{d x} = 0.2 \cdot + y + 200

6 y^{^{'}} + 9 y = 0

f^{^{'}} (x) - 2 f (x) (x^{2} e^{x}) = 0