4x^2y^'=y^'+6xe^{-y}

Lösung

4 x^{2} y^{^{'}} = y^{^{'}} + 6 x e^{- y}

y = ln (\frac{3}{4} ln (4 x^{2} - 1) + c_{1})

Schritte zur Lösung

4 x^{2} y^{'} (x) = y^{'} (x) + 6 x e^{- y}

Solve separable ODE:

y = ln (\frac{3}{4} ln (4 x^{2} - 1) + c_{1})

y = ln (\frac{3}{4} ln (4 x^{2} - 1) + c_{1})

\frac{d}{d x} (6 x e^{x})

t an g e n t f (x) = x^{3} - 3 x^{2} + 2 x - 2, at x = 0

\frac{\partial}{\partial y} (\frac{3 x - 4 y}{3 x + 4 y})

x \to 9 lim (cos (\frac{1}{x - 9}))

d er i v a t i v e 3 6 x