y^'=y^2(x)cos(x)

Lösung

y^{^{'}} = y^{2} (x) cos (x)

y = - \frac{1}{x sin ( x ) + cos ( x ) + c _{1}}

Schritte zur Lösung

y^{'} (x) = y^{2} (x) cos (x)

Solve separable ODE:

y = - \frac{1}{x sin ( x ) + cos ( x ) + c _{1}}

y = - \frac{1}{x sin ( x ) + cos ( x ) + c _{1}}

(\frac{d y}{d x}) - y x = 0

\frac{d y}{d x} = 70 y x^{6}, y = 6

\frac{d v}{d t} = v \cdot t^{3} - 1.5 \cdot v, v (0) = 1

y = x^{2} \frac{d y}{d x}

y^{^{'}} + 50 y = 5, y (0) = 0, y (0) = 0