y^{'''}-y^'=3cos(x)

Lösung

y^{^{'''}} - y^{^{'}} = 3 cos (x)

y = c_{1} + c_{2} e^{- x} + c_{3} e^{x} - \frac{3}{2} sin (x)

Schritte zur Lösung

y^{'''} (x) - y^{'} (x) = 3 cos (x)

Solve linear ODE:

y = c_{1} + c_{2} e^{- x} + c_{3} e^{x} - \frac{3}{2} sin (x)

y = c_{1} + c_{2} e^{- x} + c_{3} e^{x} - \frac{3}{2} sin (x)

y^{^{''}} - y^{^{'}} - 2 y = 3 x + 4

y^{^{''}} + 4 y = \frac{e ^{2 x}}{x}

y^{^{''}} - y^{^{'}} - 2 y = e^{3 t}

y^{^{''}} - y = 3 x^{2} - 1

y^{^{''}} - 4 y^{^{'}} + 4 y = 2 e^{2 t} + 4 t^{2}