y^{''}-y^'=2x+4

Lösung

y^{^{''}} - y^{^{'}} = 2 x + 4

y = c_{1} e^{x} + c_{2} - x^{2} - 6 x

Schritte zur Lösung

y^{''} (x) - y^{'} (x) = 2 x + 4

Solve linear ODE:

y = c_{1} e^{x} + c_{2} - x^{2} - 6 x

y = c_{1} e^{x} + c_{2} - x^{2} - 6 x

y^{^{''}} + 2 y^{^{'}} + 5 = 0

y^{^{''}} + y = 2 e^{3 x}

y^{^{''}} + 2 y^{^{'}} + y = e^{3 x}

4 y^{^{''}} + 36 y = sec (3 x)

y^{^{''}} - 4 y^{^{'}} - 5 y = 24 x e^{5 x} - 26 sin (x)