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Popular >

D(t)=t+5

Solution

D (t) = t + 5

Solution

t = \frac{5}{D - 1}; D \neq = 1

Solution steps

D (t) = t + 5

Expand

D (t) : D t

D t = t + 5

Move

t

to the left side

D t - t = 5

Factor

D t - t : t (D - 1)

t (D - 1) = 5

Divide both sides by

D - 1; D \neq = 1

t = \frac{5}{D - 1}; D \neq = 1

Graph

Popular Examples

y^{''}+2y^'-y=t^{-1}e^t

y^{^{''}} + 2 y^{^{'}} - y = t^{- 1} e^{t}

y^{''}-4y^'-12y=4

y^{^{''}} - 4 y^{^{'}} - 12 y = 4

y^{''}-2y^'+2y=sin(t),y(0)=0,y^'(0)=1

y^{^{''}} - 2 y^{^{'}} + 2 y = sin (t), y (0) = 0, y^{^{'}} (0) = 1

y^{''}-5y^'+6y=3x^2+5x

y^{^{''}} - 5 y^{^{'}} + 6 y = 3 x^{2} + 5 x

y^{''}+2y^'-3y=5e^{2x},y(0)=0,y^'(0)=a

y^{^{''}} + 2 y^{^{'}} - 3 y = 5 e^{2 x}, y (0) = 0, y^{^{'}} (0) = a

Frequently Asked Questions (FAQ)

What is the answer to D(t)=t+5 ?
The answer to D(t)=t+5 is t= 5/(D-1);\quad D\ne 1