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Beliebt Rechnen >

y^{''}+9y=cos(t),y(0)=0,y^'(0)=0

Lösung

y^{^{''}} + 9 y = cos (t), y (0) = 0, y^{^{'}} (0) = 0

Lösung

y = \frac{1}{8} cos (t) - \frac{1}{8} cos (3 t)

Schritte zur Lösung

y^{''} (t) + 9 y = cos (t)

Solve linear ODE:

y = \frac{1}{8} cos (t) - \frac{1}{8} cos (3 t)

y = \frac{1}{8} cos (t) - \frac{1}{8} cos (3 t)

Graph

Beliebte Beispiele

y^{^{''}} + 6 y^{^{'}} = 2

y^{^{''}} + 6 y^{^{'}} = 1

y^{''}+2y^'+2y=((e^{-x}))/(cos(x))

y^{^{''}} + 2 y^{^{'}} + 2 y = \frac{( e ^{- x} )}{cos ( x )}

(d^2y)/(dx^2)+4y=2sin(2x)

\frac{d ^{2} y}{d x ^{2}} + 4 y = 2 sin (2 x)

y^{''}-2y^'-3y=3*e^{-t}

y^{^{''}} - 2 y^{^{'}} - 3 y = 3 \cdot e^{- t}