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Beliebt Rechnen >

y^{''}+y=2,y(0)=4,y^'(0)=2

Lösung

y^{^{''}} + y = 2, y (0) = 4, y^{^{'}} (0) = 2

Lösung

y = 2 cos (t) + 2 sin (t) + 2

Schritte zur Lösung

y^{''} (t) + y = 2

Solve linear ODE:

y = 2 cos (t) + 2 sin (t) + 2

y = 2 cos (t) + 2 sin (t) + 2

Graph

Beliebte Beispiele

y^{''}+y^'-3y=e^{2x}

y^{^{''}} + y^{^{'}} - 3 y = e^{2 x}

y^{''}+6y^'+5y=36e^x

y^{^{''}} + 6 y^{^{'}} + 5 y = 36 e^{x}

y^{'''}-y^{''}=x-2

y^{^{'''}} - y^{^{''}} = x - 2

(d^2y)/(dx^2)+2(dy)/(dx)+y=cos^2(x)

\frac{d ^{2} y}{d x ^{2}} + 2 \frac{d y}{d x} + y = cos^{2} (x)

y^{''}+6y^'+9y=(e^{-3x})/(x^2+1)

y^{^{''}} + 6 y^{^{'}} + 9 y = \frac{e ^{- 3 x}}{x ^{2} + 1}