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Beliebt Rechnen >

y^{''}-y^'+2y=x

Lösung

y^{^{''}} - y^{^{'}} + 2 y = x

Lösung

y = e^{\frac{x}{2}} (c_{1} cos (\frac{7 x}{2}) + c_{2} sin (\frac{7 x}{2})) + \frac{x}{2} + \frac{1}{4}

Schritte zur Lösung

y^{''} (x) - y^{'} (x) + 2 y = x

Solve linear ODE:

y = e^{\frac{x}{2}} (c_{1} cos (\frac{7 x}{2}) + c_{2} sin (\frac{7 x}{2})) + \frac{x}{2} + \frac{1}{4}

y = e^{\frac{x}{2}} (c_{1} cos (\frac{7 x}{2}) + c_{2} sin (\frac{7 x}{2})) + \frac{x}{2} + \frac{1}{4}

Graph

Beliebte Beispiele

2y^{''}+2y^'+2y=sin(t)+1

2 y^{^{''}} + 2 y^{^{'}} + 2 y = sin (t) + 1

u^{''}+au^'(t)=b

u^{^{''}} + a u^{^{'}} (t) = b

6y^{''}+3y^'-30y=16cos(x)

6 y^{^{''}} + 3 y^{^{'}} - 30 y = 16 cos (x)

y^{''}-5y^'-36y=e^{9x}

y^{^{''}} - 5 y^{^{'}} - 36 y = e^{9 x}

y^{''}+y^'+y=sin(x)+x+x^2-1

y^{^{''}} + y^{^{'}} + y = sin (x) + x + x^{2} - 1