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Beliebt Rechnen >

y^{''}+y=e^{2x},y(0)=0

Lösung

y^{^{''}} + y = e^{2 x}, y (0) = 0

Lösung

y = - \frac{1}{5} cos (x) + c_{2} sin (x) + \frac{1}{5} e^{2 x}

Schritte zur Lösung

y^{''} (x) + y = e^{2 x}

Solve linear ODE:

y = - \frac{1}{5} cos (x) + c_{2} sin (x) + \frac{1}{5} e^{2 x}

y = - \frac{1}{5} cos (x) + c_{2} sin (x) + \frac{1}{5} e^{2 x}

Graph

Beliebte Beispiele

y^{''}-2y^'-3y=xe^{-x}

y^{^{''}} - 2 y^{^{'}} - 3 y = x e^{- x}

x^{^{''}} + x = 2 e^{t}

y^{''}-4y^'+4y=2x^2+4xe^{2x}+xsin(2x)

y^{^{''}} - 4 y^{^{'}} + 4 y = 2 x^{2} + 4 x e^{2 x} + x sin (2 x)

y^{^{''}} = x - y

y^{''}+y^'-12y=4,y(0)=0,y^'(0)=0

y^{^{''}} + y^{^{'}} - 12 y = 4, y (0) = 0, y^{^{'}} (0) = 0