y^{''}+25y=8cos(5x)

Lösung

y^{^{''}} + 25 y = 8 cos (5 x)

y = c_{1} cos (5 x) + c_{2} sin (5 x) + \frac{4 x sin ( 5 x )}{5}

Schritte zur Lösung

y^{''} (x) + 25 y = 8 cos (5 x)

Solve linear ODE:

y = c_{1} cos (5 x) + c_{2} sin (5 x) + \frac{4 x sin ( 5 x )}{5}

y = c_{1} cos (5 x) + c_{2} sin (5 x) + \frac{4 x sin ( 5 x )}{5}

y^{^{''}} + a^{2} y = b cos (c x), y (0) = 0, y^{^{'}} (0) = 0

y^{^{''}} - y^{^{'}} - 2 y = \frac{1}{2} e^{2 t} + \frac{1}{2} e^{- 2 t}

y^{^{''}} + 5 y^{^{'}} = 29 sin (- 2 t)

(D^{2} + 3 D + 2) y = sin (2 x)

y^{^{''}} - 3 y^{^{'}} + 2 y = 11 e^{3 x}, y (0) = e^{x}