y^{''}-y^'-2y=8x+6

Lösung

y^{^{''}} - y^{^{'}} - 2 y = 8 x + 6

y = c_{1} e^{2 x} + c_{2} e^{- x} - 4 x - 1

Schritte zur Lösung

y^{''} (x) - y^{'} (x) - 2 y = 8 x + 6

Solve linear ODE:

y = c_{1} e^{2 x} + c_{2} e^{- x} - 4 x - 1

y = c_{1} e^{2 x} + c_{2} e^{- x} - 4 x - 1

y^{^{''}} + 7 y + 6 y = e^{6 x}

9 y^{^{''}} - 6 y^{^{'}} + y = 8

y^{^{''}} + 4 y = - 4 sin (2 x)

l in e a r y^{^{''}} - 2 y^{^{'}} + y = x^{3} + 4 x

y^{^{''}} + 2 y = - sec (x)