What is the solution for y^{''}-y=13t,y(0)=-13t ?

The solution for y^{''}-y=13t,y(0)=-13t is y=c_{1}e^t+c_{2}e^{-t}-13t

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{''}-y=13t,y(0)=-13t

y^{^{''}} - y = 13 t, y (0) = - 13 t

y = c_{1} e^{t} + c_{2} e^{- t} - 13 t

Solution steps

y^{''} (t) - y = 13 t

Solve linear ODE:

y = c_{1} e^{t} + c_{2} e^{- t} - 13 t

y = c_{1} e^{t} + c_{2} e^{- t} - 13 t

y^{^{''}} + y = 2 sin (2 t), y^{^{'}} (0) = 10

y^{^{''}} - y^{^{'}} = x^{3}

x^{^{''}} - 2 x^{^{'}} + 10 x = 7 cos (t)

y^{^{''}} - y^{^{'}} - 6 y = e^{2 t}, y^{^{'}} (0) = 1, y (0) = 3

y^{^{''}} - 4 y = 14 cos (2 x) + 21 sin (2 x)

What is the solution for y^{''}-y=13t,y(0)=-13t ?
The solution for y^{''}-y=13t,y(0)=-13t is y=c_{1}e^t+c_{2}e^{-t}-13t