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Beliebt Rechnen >

x^{''}+2x^'+2x=2,x(0)=0,x^'(0)=0

Lösung

x^{^{''}} + 2 x^{^{'}} + 2 x = 2, x (0) = 0, x^{^{'}} (0) = 0

Lösung

x = e^{- t} (- cos (t) - sin (t)) + 1

Schritte zur Lösung

x^{''} (t) + 2 x^{'} (t) + 2 x = 2

Solve linear ODE:

x = e^{- t} (- cos (t) - sin (t)) + 1

x = e^{- t} (- cos (t) - sin (t)) + 1

Graph

Beliebte Beispiele

y^{''}=2y+tan^3(x),y^1(x)= 1/2 tan(x)

y^{^{''}} = 2 y + tan^{3} (x), y^{1} (x) = \frac{1}{2} tan (x)

y^{''}-11y^'+28y=108e^t

y^{^{''}} - 11 y^{^{'}} + 28 y = 108 e^{t}

y^{''}-2y^'+y=x-2-2cos(8)

y^{^{''}} - 2 y^{^{'}} + y = x - 2 - 2 cos (8)

y^{''}+4y^'=4x+1

y^{^{''}} + 4 y^{^{'}} = 4 x + 1

y^{''}+y^'-12=0

y^{^{''}} + y^{^{'}} - 12 = 0