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Beliebt Rechnen >

y^{''}-2y^'+10y=0,y(0)=4,y^'(0)=5

Lösung

y^{^{''}} - 2 y^{^{'}} + 10 y = 0, y (0) = 4, y^{^{'}} (0) = 5

Lösung

y = e^{t} (4 cos (3 t) + \frac{1}{3} sin (3 t))

Schritte zur Lösung

y^{''} (t) - 2 y^{'} (t) + 10 y = 0

Solve linear ODE:

y = e^{t} (4 cos (3 t) + \frac{1}{3} sin (3 t))

y = e^{t} (4 cos (3 t) + \frac{1}{3} sin (3 t))

Graph

Beliebte Beispiele

(d^2y)/(dx^2)-2(dy)/(dx)+5y=0

\frac{d ^{2} y}{d x ^{2}} - 2 \frac{d y}{d x} + 5 y = 0

1/(pi^2)x^{''}+16x=0

\frac{1}{π ^{2}} x^{^{''}} + 16 x = 0

2y^{''}-y^'-3y=0

2 y^{^{''}} - y^{^{'}} - 3 y = 0

(3D^3+5D^2-2D)y=0

(3 D^{3} + 5 D^{2} - 2 D) y = 0

y^{'''}-y^{''}=0,y(0)=2,y^'(0)=0,y^{''}(0)=1

y^{^{'''}} - y^{^{''}} = 0, y (0) = 2, y^{^{'}} (0) = 0, y^{^{''}} (0) = 1