y^{''}-16y^'=0

Lösung

y^{^{''}} - 16 y^{^{'}} = 0

y = c_{1} e^{16 t} + c_{2}

Schritte zur Lösung

y^{''} (t) - 16 y^{'} (t) = 0

Solve linear ODE:

y = c_{1} e^{16 t} + c_{2}

y = c_{1} e^{16 t} + c_{2}

x^{^{''}} + 5 x^{^{'}} + 4 x = 0

y^{^{''}} + 4 y = 0, y (\frac{π}{6}) = 1, y^{^{'}} (\frac{π}{6}) = - 2

y^{^{''}} + y^{^{'}} + \frac{5}{4} y = 0, y (0) = 3, y^{^{'}} (0) = 1

y^{^{''}} + 2 y^{^{'}} + y = 0, y^{^{'}} (0) = 8, y (1) = 8

y^{^{''}} - 2 y^{^{'}} + 10 y = 0, y (0) = 0, y^{^{'}} (0) = 0