x^{''}-9x=0

Lösung

x^{^{''}} - 9 x = 0

x = c_{1} e^{3 t} + c_{2} e^{- 3 t}

Schritte zur Lösung

x^{''} (t) - 9 x = 0

Solve linear ODE:

x = c_{1} e^{3 t} + c_{2} e^{- 3 t}

x = c_{1} e^{3 t} + c_{2} e^{- 3 t}

y^{^{''}} - 3 y^{^{'}} + 2 y = 0, y (1) = 0, y^{^{'}} (1) = 1

y^{^{''''}} + 3 y^{^{'''}} + 3 y^{^{''}} + y^{^{'}} = 0

y^{^{''}} - 2 y^{^{'}} + y = 0, y (2) = 0, y^{^{'}} (2) = 1

2 y^{^{'''}} - 4 y^{^{''}} - 2 y^{^{'}} + 4 y = 0

\frac{d ^{2} y}{d x ^{2}} - 4 \frac{d y}{d x} + 5 y = 0