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Beliebt Rechnen >

2y^{''}+5y^'+2y=0

Lösung

2 y^{^{''}} + 5 y^{^{'}} + 2 y = 0

Lösung

y = c_{1} e^{- \frac{t}{2}} + c_{2} e^{- 2 t}

Schritte zur Lösung

2 y^{''} (t) + 5 y^{'} (t) + 2 y = 0

Solve linear ODE:

y = c_{1} e^{- \frac{t}{2}} + c_{2} e^{- 2 t}

y = c_{1} e^{- \frac{t}{2}} + c_{2} e^{- 2 t}

Graph

Beliebte Beispiele

y^{''}-4y^'-5y=0,y(0)=2,y^'(0)=3

y^{^{''}} - 4 y^{^{'}} - 5 y = 0, y (0) = 2, y^{^{'}} (0) = 3

(d^5+8d^3+16d)y=0

(d^{5} + 8 d^{3} + 16 d) y = 0

(d^2x)/(dt^2)+81x=0

\frac{d ^{2} x}{d t ^{2}} + 81 x = 0

1/4 y^{''}+y^'+4y=0

\frac{1}{4} y^{^{''}} + y^{^{'}} + 4 y = 0

y^{'''}+5y^{''}+3y^'-9y=0

y^{^{'''}} + 5 y^{^{''}} + 3 y^{^{'}} - 9 y = 0