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Beliebt Rechnen >

2x^{''}+4x^'+10x=0

Lösung

2 x^{^{''}} + 4 x^{^{'}} + 10 x = 0

Lösung

x = e^{- t} (c_{1} cos (2 t) + c_{2} sin (2 t))

Schritte zur Lösung

2 x^{''} (t) + 4 x^{'} (t) + 10 x = 0

Solve linear ODE:

x = e^{- t} (c_{1} cos (2 t) + c_{2} sin (2 t))

x = e^{- t} (c_{1} cos (2 t) + c_{2} sin (2 t))

Graph

Beliebte Beispiele

4y^{''}+4y^'+4y=0

4 y^{^{''}} + 4 y^{^{'}} + 4 y = 0

5 y^{^{''}} + 5 y = 0

4y^{''}-2y^'-2y=0,y(0)=4,y^'(0)=1

4 y^{^{''}} - 2 y^{^{'}} - 2 y = 0, y (0) = 4, y^{^{'}} (0) = 1

y^{''}+2y^'+10y=0,y(0)=0

y^{^{''}} + 2 y^{^{'}} + 10 y = 0, y (0) = 0

y^{''}+2y^'+y=0,y^1(0)=xe-x

y^{^{''}} + 2 y^{^{'}} + y = 0, y^{1} (0) = x e - x