integral of (x^3-10x-3)

解答

\int (x^{3} - 10 x - 3) d x

\frac{x ^{4}}{4} - 5 x^{2} - 3 x + C

求解步骤

\int x^{3} - 10 x - 3 d x

使用积分加法定则:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x^{3} d x - \int 10 x d x - \int 3 d x

\int x^{3} d x = \frac{x ^{4}}{4}

\int 10 x d x = 5 x^{2}

\int 3 d x = 3 x

= \frac{x ^{4}}{4} - 5 x^{2} - 3 x

解答补常数

= \frac{x ^{4}}{4} - 5 x^{2} - 3 x + C

d er i v a t i v e a^{3} + cos^{3} (x)

\frac{d}{d x} (ln (1 - 2 x))

x \to \infty lim (10)

n = 1 \sum \infty \frac{n !}{10 6 ^{n}}

\frac{d}{d t} (e^{3 t s i n (2 t)})