y^{''}-8y^'-7y=0

Lösung

y^{^{''}} - 8 y^{^{'}} - 7 y = 0

y = c_{1} e^{(4 + 23) t} + c_{2} e^{(4 - 23) t}

Schritte zur Lösung

y^{''} (t) - 8 y^{'} (t) - 7 y = 0

Solve linear ODE:

y = c_{1} e^{(4 + 23) t} + c_{2} e^{(4 - 23) t}

y = c_{1} e^{(4 + 23) t} + c_{2} e^{(4 - 23) t}

x^{^{''}} + 6 x^{^{'}} + 9 x = 0, x (0) = a, x^{^{'}} (0) = b

y^{^{''}} + 14 y^{^{'}} + 49 y = 0, y (0) = - 1, y^{^{'}} (0) = 1

y^{^{''''}} - 3 y^{^{'''}} - 4 y^{^{''}} = 0

2 y^{^{''}} - 2 y^{^{'}} + 4 y = 0

y^{^{''}} + 4 y^{^{'}} - 5 y = 0, y (0) = - 3, y^{^{'}} (0) = 21