5y^{''}+20y=0,y(pi/4)=10,y(0)=15

Lösung

5 y^{^{''}} + 20 y = 0, y (\frac{π}{4}) = 10, y (0) = 15

y = 15 cos (2 t) + 10 sin (2 t)

Schritte zur Lösung

5 y^{''} (t) + 20 y = 0

Solve linear ODE:

y = 15 cos (2 t) + 10 sin (2 t)

y = 15 cos (2 t) + 10 sin (2 t)

2 y^{^{''}} + 6 y^{^{'}} = 0

\frac{d ^{2} y}{d x ^{2}} + k \frac{d y}{d x} - k^{2} y = 0

y^{^{''}} + 2 y^{^{'}} + y = 0, y (0) = 10, y^{^{'}} (0) = - 9

y^{^{''}} - 4 y^{^{'}} - 4 y = 0, y (0) = 1, y^{^{'}} (0) = 5

y^{^{''}} - 4 y^{^{'}} - 4 y = 0, y (0) = 2, y^{^{'}} (0) = 16