What is the solution for (d^2y)/(dt^2)-10(dy)/(dt)=0 ?

The solution for (d^2y)/(dt^2)-10(dy)/(dt)=0 is y=c_{1}e^{10t}+c_{2}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(d^2y)/(dt^2)-10(dy)/(dt)=0

\frac{d ^{2} y}{d t ^{2}} - 10 \frac{d y}{d t} = 0

y = c_{1} e^{10 t} + c_{2}

Solution steps

\frac{d ^{2} y}{d t ^{2}} - 10 \frac{d y}{d t} = 0

Solve linear ODE:

y = c_{1} e^{10 t} + c_{2}

y = c_{1} e^{10 t} + c_{2}

y^{^{''}} - 4 y + 13 y = 0

49 y^{^{'''}} + 56 y^{^{''}} + 16 y^{^{'}} = 0

\frac{d ^{3} y}{d x ^{3}} + 8 \frac{d y}{d x} = 0

y^{^{''}} - 10 y^{^{'}} + 25 y = 0, y (0) = 2, y^{^{'}} (0) = 5

y^{^{''}} - 10 y^{^{'}} + 25 y = 0, y (0) = 2, y^{^{'}} (0) = 4

What is the solution for (d^2y)/(dt^2)-10(dy)/(dt)=0 ?
The solution for (d^2y)/(dt^2)-10(dy)/(dt)=0 is y=c_{1}e^{10t}+c_{2}